链表常见解法:
使用前后指针, 前指针遍历完时后指针指向删除节点;

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/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
ListNode dummy=new ListNode(0,head);
ListNode back = dummy;
ListNode front = head;
for(int i=0;i<n;i++){
front=front.next;
}
while(front!=null){
front=front.next;
back=back.next;
}
back.next=back.next.next;
return dummy.next;
}
}